Show that y – 1 is a factor of y10 – 1 .
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p(x)=y¹⁰-1
g(x)=y-1
To get zero , g(x)=0
y-1=0
y=1
p(1)= (1)¹⁰-1
= 0
Since the remainder is zero
Therefore, g(x) is the factor of p(x)
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