Show that (y+4),(y-7) and (y-3) are the factor of y3-6y2-19y+84
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Answered by
1
We can show that by multiplying all of the nos.
that is (y+4)(y-7)(y-3)
(y^2+4y-7y-28)(y-3)
y^3-6y2-19y+84
that is (y+4)(y-7)(y-3)
(y^2+4y-7y-28)(y-3)
y^3-6y2-19y+84
Answered by
0
Answer:
we will put -4 in place X means p(-4) then solve it by placing -4 at x
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