Question

Show that y³+z³=(y+z)(y+wz)(y+w²z)
w=omega.​

Answer 1

Step-by-step explanation:

x+y+z)[x^2+y^2+ z^2-(xy+yz+zx)] ... (x + y + z)(x + ωy + ω²z)(x + ωz + ω²y) = x³ + y³ + z³ - 3xyz. ii) Since 1, ω, ...