Show that|z-3/z+3|=2 represent a circle
Answers
Answered by
1
Answer:
This is the equation of a circle with centre at (-5,0) and radius 4 units
Step-by-step explanation:
We have,
Z-3 z+3 = 2
= |z – 3| - 2|z + 3| (x – 3)+ y2 =
Let z x+iy, where x, y ER x + iy - 3 = 2 x + iy + 3
= |(x – 3) + iy 2|(x + 3) + iy|
2/(x+3)2 + y2
+ (x – 3) + y2 4[(x + 3)2 + y2
→ x + 9 - 2 6х + у?
4 [x? + 9+ 6x + y²] → x? +9 – 6x + y?
=
4x2 + 36 + 24 x
+ 4y? = 3x? + 3y? + 30x + 27 = 0 → x? + y2 + 10x + 9=0
This is the equation of a circle with centre at (-5,0) and radius 4 units
Answered by
0
Answer:
z+3/z-3=2 ok
Thank You
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