Math, asked by alasanianitha, 4 months ago

show that1)sin(11π/3).tan(35π/6).sec(-7π/3)%cos(5π/7).cosec(7π/4).cos(17π/6=2%3​

Answers

Answered by pkmondkar
0

Answer:

show that1)sin(11π/3).tan(35π/6).sec(-7π/3)%cos(5π/7).cosec(7π/4).cos(17π/6=2%3

Answered by aditya595424
1

Answer:

sin(-11*180/3)*tan(35*180/6)*sec(-7*180/3)*cos(5*180/4)

sin(-660)*tan(1050)*sec(-420)*cos(225)

sin(360*2-60)*tan(360*3-30)*sec(360+60)*cos(360-135)

-sin 60* -tan 30* sec60 *cos(180-45)

-√3/2* - 1/√3 * 2 * - 1/√2

=. -1/√2 ans.

Step-by-step explanation:

put value of π

then use 360*n +/- theta and 180+/-theta

plzz mark as brainlist

Similar questions
Math, 10 months ago