Show thatth diagonals of a parallogram divide it into fOur triangle of equal area
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Step-by-step explanation:
Let ABCD be a parallelogram with diagonals AC and BD intersecting at O. Since the diagonal of the parallelogram bisect each other at the point of intersection. Therefore AO=CO and BO=DO. Also the median median or the triangle divide it into two equal parts. Therefore (see the picture)
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