show thatthe equation has Real roots nd solve this by quadratic equation p(sqare)x(sqare)+[p(sqare)-q(sqare)]x-q(sqare)=0
Answers
Answered by
1
use the determinant formula and show that dis equal to 0 or greater than 0 to prove that the eqn has real roots
7360812608:
ya I tried but answer will not come correctly
u must be doing calculation mistake bec this is the only way.
Answered by
1
Answer:
HEY .....(^_^)
√3 + √2 / √3 - √2
= (√3 + √2 / √3 - √2 ) × ( √3 + √2 / √3 + √2)
= (√3 + √2)^2 / (√3)^2 - (√2)^2
= [ (√3)^2 + (√2)^2 + 2×√3×√2 ] / 3-2
= 3 + 2 + 2√6 / 1
= 5 + 2√6
Step-by-step explanation: hloooooooooooooooooiiiooiioiii
Similar questions