Question

show thatthe progression 1/6,1/3,1/2,2/3...... is an A.P. write the next three terms of this A.P​

Answer 1

Answer:

hiiii

Step-by-step explanation:

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Answer 2

Answer:

ANSWER

ANSWERpH is the negative log of H

ANSWERpH is the negative log of H +

ANSWERpH is the negative log of H + concentration

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H +

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H + ]

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H + ]pH=−log(3.8×10

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H + ]pH=−log(3.8×10 −3

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H + ]pH=−log(3.8×10 −3 )=−[log3.8+log 10

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H + ]pH=−log(3.8×10 −3 )=−[log3.8+log 10 −3

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H + ]pH=−log(3.8×10 −3 )=−[log3.8+log 10 −3 ]=2.42

ANSWERpH is the negative log of H + concentrationi.e pH=−log[H + ]pH=−log(3.8×10 −3 )=−[log3.8+log 10 −3 ]=2.42Hence, option C is correct.