show thatx=-3is a solution of the equation x^2+6x+9=0
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If we put the value x = (-3), then x²+6x+9 = (-3)² + 6(-3) + 9 = 9 + 18 - 9 = 0
Since the value became 0, it is a root of the given equation..
Since the value became 0, it is a root of the given equation..
Answered by
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Hii
we know that x= -3
so
square of x + 6x+9=0
(-3×-3)+ (6×-3)+9=0
9+(-18)+9=0
18-18=0
0=0
LH =RS
we know that x= -3
so
square of x + 6x+9=0
(-3×-3)+ (6×-3)+9=0
9+(-18)+9=0
18-18=0
0=0
LH =RS
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