show thatxyz is exactly divisible by 99 after taking the difference of original number and reversed number
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given no. xyz
it is expanded as 100x+10y+z
therefore original no. =100x+10y+z
no. when reversed=zyx
it can be expanded as 100z+10y+x
therefore reversed no. is 100z+10y+x
original no. -reversed no.
100x+10y+z-(100z+10y+x)
99x+99z
99(x+z)
when we divide it by 99 we get x+z which is exactly divisible
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