Math, asked by unmeshgaonkar0777, 4 months ago

Show the AB is non-
non- singular
and B are
Singular matrix, where &
A=[4 0 3]
[ 1 2 -2] and
B =[02]
[1 3]
[21]​

Answers

Answered by sarasuniradhara447
0

Answer:

IfA and B are square matrices of order $43.Aisnon−singularandAB=0$$ then one may non-singular matrix not both

Given

∣AB∣=0

∣AB∣=∣A∣∣B∣

now,weconclude

∣A∣∣B∣=0

so,either∣A∣=0or∣B∣=0

∴eitherAorBmustbenon−singular.

Hence,option C is the correct answer.

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