Show the AB is non-
non- singular
and B are
Singular matrix, where &
A=[4 0 3]
[ 1 2 -2] and
B =[02]
[1 3]
[21]
Answers
Answered by
0
Answer:
IfA and B are square matrices of order $43.Aisnon−singularandAB=0$$ then one may non-singular matrix not both
Given
∣AB∣=0
∣AB∣=∣A∣∣B∣
now,weconclude
∣A∣∣B∣=0
so,either∣A∣=0or∣B∣=0
∴eitherAorBmustbenon−singular.
Hence,option C is the correct answer.
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