Computer Science, asked by kashishjuneja046, 20 days ago

Show the contents in hexadecimal of registers PC, AR, DR, IR, and SC of the basic computer when an ISZ indirect instruction is fetched from memory and executed. The initial content of PC is 7FF. The content of memory at address 7FF is EA9F. The content of memory at address A9F is 0C35. The content of memory at address C35 is FFFF. Give the answer in a table with five columns one for each register and a row for each timing signal . Show the contents of the registers after the positive transition of each clock pulse.​

Answers

Answered by shashanklagudu
4

Answer:

The content of PC in the basic computer is 3AF (all numbers are in hexadecimal). The content of AC is 7EC3. The content of memory at address 3AF is 932E. The content of memory at address 32E is 09AC. The content of memory at address 9AC is 8B9F.

a. What is the instruction that will be fetched and executed next?

b. Show the binary operation that will be performed in the AC when the instruction is executed.

c. Give the contents of registers PC, AR, DR, AC, and IR in hexadecimal and the values of E, I, and the sequence counter SC in binary at the end of the instruction cycle

Answered by SahiliDessai1998
0

Explanation:

Display the values of the basic computer's registers PC, AR, DR, IR, and SC in hexadecimal when an ISZ indirect instruction is read from memory and carried out. PC's initial contents are 7FF. Memory at location 7FF has the value EA9F. Memory block OC35 is located at address A9F. Memory at location C35 has the value FFFF in it. In a table with five columns, one for each register and a row for each timing signal, present the solution. Immediately following each clock pulse's positive transition, display the contents of the registers.

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