Question

show the cross of(RRYY×rryy).Also tell the phenotypic and genotypic ratio.​

Answer 1

Answer:

A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.

The dihybrid phenotypic ratio is 9:3:3:1.i.e. 9 round-yellow : 3 wrinkled-yellow : 3 round-green : 1 wrinkled-green pea seeds

In F2 generation, we will get the following combination of gametes - RY Ry rY ry RY. When crossed, they would give the following possible offspring:

1 YYRR + 2 YYRr + 1 YYrr + 2YyRR + 4YyRr + 2 yyRR + 1yyRR + 2yyRr + 1yyrr

Thus the genotype ratio is 1:2:1:2:4:2:1:2:1.

Hope this answer helps you out.