Show the equation 2 ✖ 2+5√3+6=0 has real roots solve it
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Answer:
-5✓3+✓27÷4 and -5✓3-✓27÷4
Step-by-step explanation:
a=2 b=5✓3 c=6
D= (b)² - 4ac
= (5✓3)² - 4 (2) (6)
= 75 - 48
= 27
as 27 < 0 , the equation has real roots
Roots:
x= -b±✓D÷ 2a
= -5✓3 ±✓27 ÷ 4
therefore roots are -5✓3+✓27÷4 and -5✓3-✓27÷4
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