show the exactly one of the number n, n+2,n+4divisible by 3
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Answered by
5
here is ur answer buddy......
let n= 3q, 3q+1 or 3q+2 for a positive integer q
case 1 :
n=3q
I)
n=3q
which shows that 3 divides n
=>n is divisible by 3
ii)
n+2=3q+2
here , this leaves a remainder of 2
=>n+2 is not divisible by 3
iii)
n+4=3q+4
here this leaves a remainder if 4
it is not divisible by3
let n= 3q, 3q+1 or 3q+2 for a positive integer q
case 1 :
n=3q
I)
n=3q
which shows that 3 divides n
=>n is divisible by 3
ii)
n+2=3q+2
here , this leaves a remainder of 2
=>n+2 is not divisible by 3
iii)
n+4=3q+4
here this leaves a remainder if 4
it is not divisible by3
jude0704:
welcome
Answered by
0
Answer:
ANSWER IS HERE GUYS
Step-by-step explanation:
let n= 3q, 3q+1 or 3q+2 for a positive integer q
case 1 :
n=3q
I)
n=3q
which shows that 3 divides n
=>n is divisible by 3
ii)
n+2=3q+2
here , this leaves a remainder of 2
=>n+2 is not divisible by 3
iii)
n+4=3q+4
here this leaves a remainder if 4
it is not divisible by 3
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