Show the formation of na20 and mg0 by the transfer of electrons
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Atomic number of Sodium (Na) – 11Electronic configuration of Sodium – 1s2 2s22p6 3s1 It has one valence electron, it will lose one electron to get octet configuration Atomic number of Oxygen (O) – 8 Electronic configuration of Oxygen – 1s2 2s2 2p4 It is two electrons short of octet configuration, thus it will gain two electrons. During the bond formation between Sodium and Oxygen, two Sodium atoms loses one electron each to Oxygen atom. 2 Na -2e- → 2Na+ O + 2e- → O-2 2Na+ + O-2 → Na2O Atomic number of Magnesium (Mg) – 12 Electronic configuration of Magnesium – 1s2 2s2 2p6 3s2It has two valence electrons, it will lose two electrons to get octet configuration Atomic number of Oxygen (O) – 8 Electronic configuration of Oxygen – 1s2 2s2 2p4 It is two electrons short of octet configuration, thus it will gain two electrons. During the bond formation between Magnesium and Oxygen, one Magnesium atom loses two electrons to Oxygen atom. Mg -1e- → Mg2+ O + 2e- → O-2 Mg+2 + O-2 → MgO
Atomic number of Sodium (Na) – 11Electronic configuration of Sodium – 1s2 2s22p6 3s1 It has one valence electron, it will lose one electron to get octet configuration Atomic number of Oxygen (O) – 8 Electronic configuration of Oxygen – 1s2 2s2 2p4 It is two electrons short of octet configuration, thus it will gain two electrons. During the bond formation between Sodium and Oxygen, two Sodium atoms loses one electron each to Oxygen atom. 2 Na -2e- → 2Na+ O + 2e- → O-2 2Na+ + O-2 → Na2O Atomic number of Magnesium (Mg) – 12 Electronic configuration of Magnesium – 1s2 2s2 2p6 3s2It has two valence electrons, it will lose two electrons to get octet configuration Atomic number of Oxygen (O) – 8 Electronic configuration of Oxygen – 1s2 2s2 2p4 It is two electrons short of octet configuration, thus it will gain two electrons. During the bond formation between Magnesium and Oxygen, one Magnesium atom loses two electrons to Oxygen atom. Mg -1e- → Mg2+ O + 2e- → O-2 Mg+2 + O-2 → MgO
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