show the formation of na2o and go by the transfer of electrons ?
Answers
Answer:
By losing valence electron, sodium is changed into Na+ and by gaining two electrons lost by two sodium atoms, oxygen atom is changed into an oxide anion, O2-. In this process, both the atoms, sodium and oxygen, obtain the stable electronic configuration of the noble gas neon.
Answer:
Atomic number of sodium - 11
Electronic configuration of sodium - 1s
2
2s
2
2p
6
3s
1
It has one valence electron, it will lose one electron to get octet configuration
Atomic number of oxygen - 8
Electronic configuration of oxygen - 1s
2
2s
2
2p
4
It is two electrons short of octet configuration, thus it will gain two electrons.
During the bond formation between sodium and oxygen, two sodium atoms loses one electron each to oxygen atom,
2Na−2e
−
→2Na
+
O+2e
−
→O
−2
2Na
+
+O
−2
→Na
2
O
Atomic number of Magnesium - 12
Electronic configuration of Magnesium -1s
2
2s
2
2p
6
3s
2
It has two valence electrons , it will lose two electrons to get octet configuration
Atomic number of oxygen -8
Electronic configuration of oxygen −1s
2
2s
2
2p
4
It is two electrons short octet configuration, thus it will gain two electrons.
During the bond formation between Magnesium and Oxygen, one magnesium atom loses two electrons to oxygen atom.
Mg−2e
−
→Mg
2+
O+2e
−
→O
−2
Mg
+2
+O
−2
→MgO