Question

Show the formation of Na2O and MgO by the transfer of electrons.​

Answer 1

Answer:

Since , For Compound Making We Have to Know

about the Valency of each Elements & For this We have to Write Their Electronic Configuration with the Help of Their Atomic Number .

Sodium ( Na ) : -

Na ( 11 ) => 1s^2 2s ^2 2p^6 3s^1

As , it's Valence Shell is 3rd

So , Valence Electron = 1

& , Therefore VALENCY = 1

( Since Less than 5 )

OXYGEN (O ) : -

O ( 8 ) => 1s^2 2s^2 2p^4

As , it's Valence Shell is 2nd

So , Valence Electron = 2 + 4 = 6

& , Therefore VALENCY = 2

[ Since , more than 5 ; So { 8 - 6 = 2 } ]

MAGNESIUM ( Mg ) : -

Mg ( 12 ) => 1s^2 2s ^2 2p^6 3s^2

As , it's Valence Shell is 3rd

So , Valence Electron = 2

& , Therefore VALENCY = 2

( Since Less than 5 )

NOW , FOR Compounds : -

1 => Na2O ,

As Their Ions are Na+ & O -2

i.e , 2 atoms of Sodium are Required for 1 atom of Oxygen .

Na + O -2

\ /

1 2

=> Na2O

2 => MgO ,

As Their Ions are Mg +2 & O -2

& O -2 i.e , 1 atom of Magnesium is Required

for 1 atom of Oxygen .

Mg+2 O -2

\ /

1 1

=> MgO