Show the formation of na2o by the transfer of electrons
Answers
Atomic number of Sodium (Na) – 11
Electronic configuration of Sodium – 1s2 2s2 2p6 3s1
It has one valence electron, it will lose one electron to get octet configuration
Atomic number of Oxygen (O) – 8
Electronic configuration of Oxygen – 1s2 2s2 2p4
It is two electrons short of octet configuration, thus it will gain two electrons.
During the bond formation between Sodium and Oxygen, two Sodium atoms loses one electron each to Oxygen atom.
2 Na -2e- → 2Na+
O + 2e- → O-2
2Na+ + O-2 → Na2O
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ғᴏʀᴍᴀᴛɪᴏɴ ᴏғ ᴍɢᴏ:
ɪᴛ ʜᴀs ᴛᴡᴏ ᴇʟᴇᴄᴛʀᴏɴs ɪɴ ɪᴛs ᴏᴜᴛᴇʀᴍᴏsᴛ sʜᴇʟʟ. ... ᴛʜᴇ ᴏᴘᴘᴏsɪᴛᴇʟʏ ᴄʜᴀɴɢᴇᴅ ᴍᴀɢɴᴇsɪᴜᴍ ɪᴏɴs, ᴍɢ2+ ᴀɴᴅ ᴏxɪᴅᴇ ɪᴏɴs,ᴏ2-, ᴀʀᴇ ʜᴇʟᴅ ᴛᴏɢᴇᴛʜᴇʀ ʙʏ ᴀ sᴛʀᴏɴɢ ғᴏʀᴄᴇ ᴏғ ᴇʟᴇᴄᴛʀᴏsᴛᴀᴛɪᴄ ᴀᴛᴛʀᴀᴄᴛɪᴏɴ ᴛᴏ ғᴏʀᴍ ᴍᴀɢɴᴇsɪᴜᴍ ᴏxɪᴅᴇ ᴄᴏᴍᴘᴏᴜɴᴅ ᴍɢ2+ᴏ2- ᴏʀ ᴍɢᴏ. ᴍɢᴏ ɪs ᴀɴ ɪᴏɴɪᴄ ᴄᴏᴍᴘᴏᴜɴᴅ.
