Question

Show the formation of Na2O by transfer of electrons and write the no. of ions

present in it.​

Answer 1

Answer:

Atomic number of sodium - 11 Electronic configuration of sodium - 1s22s22p63s1 It has one valence electron, it will lose one electron to get octet configuration  Atomic number of oxygen - 8 Electronic configuration of oxygen - 1s22s22p4 It is two electrons short of octet configuration, thus it will gain two electrons. During the bond formation between sodium and oxygen, two sodium atoms loses one electron each to oxygen atom, 2Na−2e−→2Na+O+2e−→O−22Na++O−2→Na2​O