show the formation of Na2s by transfer of electrons
Answers
Answer:
Answer: The formation of both the compounds are given below.
Explanation:
The given compounds are ionic compounds.
Ionic compounds are defined as the compounds which are formed by the complete transfer of electrons from one atom to another atom. In these compounds, oppositely charged ions are attracted towards each other to form a compound.
The atom which looses electrons is known as electropositive atom and it attains positive charge. The atom which gains electrons is known as electronegative atom and it attains negative charge.
These bonds are usually formed between a non-metal and a metal.
For Na_2O
Sodium is the 11th element of the periodic table having 11 electrons. The electronic configuration of this element is 1s^22s^22p^63s^1
This will loose 1 electron to form Na^+ ion.
Oxygen is the 8th element of the periodic table having 8 electrons. The electronic configuration of this element is 1s^22s^22p^4
This will gain 2 electrons to form O^{2-} ion.
To form Na_2O compound, 2 sodium ions are needed to neutralize the charge on oxygen ion.
For MgO
Magnesium is the 12th element of the periodic table having 12 electrons. The electronic configuration of this element is 1s^22s^22p^63s^2
This will loose 2 electron to form Mg^{2+} ion.
Oxygen is the 8th element of the periodic table having 8 electrons. The electronic configuration of this element is 1s^22s^22p^4
This will gain 2 electrons to form O^{2-} ion.
To form MgO compound, 1 magnesium ion is needed to neutralize the charge on oxygen ion.
Answer:
For the formation of Na2O: It is an ionic compound and sodium has 11 atomic number and oxygen has 8 atomic number. Sodium has one valance electron whereas oxygen has 6. ... Therefore two atom of sodium will combine with one atom of oxygen and each sodium will lose one electron to oxygen and therefore completing its octet.