Question

show the formation of nacl by transfer of electrons

Answer 1

atomic number of sodium(Na) is 11 atoms in last shell is 1.
atomic number of chlorine(cl) is 17 atoms in last shell is 7.
so Na gives 1 atom to chlorine.
This is complete transfer of electrons so it is ionic compound

Answer 2

Here is your answer.....

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✔ Sodium (Na) atomic no. = 11

✔ electronic configuration= 2,8,1

✔ by losing one electron of its outermost shell , it acquires the inert gas configuration of neon and changes into sodium Ion .

✔On the other hand chlorine(Cl) atomic mass= 17

✔having electronic configuration= 2 ,8 ,7

Accepts one electron released by Sodium to complete its orbit and acquire stable configuration of argon in this process chlorine is converted into chloride ion .

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Hope this helps you....✨✨