Question

Show the formation of Sodium oxide by the transfer of electron.
(Atomic number: Na - 11.0=8)​

Answer 1

Answer:

Sodium Oxide involves Sodium(Na) and Oxygen(O)

Electronic configuration of Na - 2,8,1

Electronic configuration of O - 2,6

Since, oxygen has 6 valence electron, it will require 2 foreign electrons to complete its octet.

And since we are forming Sodium oxide here and we know that sodium has only one valence electron in its outermost shell, two Na atoms will be required to complete the octet of oxygen, see the attachment for reference.

Extras:

Valency of elements.

$\begin{array}{| c | c | c |}\bf Atomic\:No. & \bf Elements & \bf Valency \\ 1 &\sf Hydrogen & 1 \\ 2 &\sf Helium & 0 \\ 3 &\sf Lithium & 1 \\ 4 &\sf Berrylium & 2 \\5 &\sf Boron & 3 \\ 6 &\sf Carbon & 4 \\ 7 &\sf Nitrogen & 3 \\ 8 &\sf Oxygen & 2 \\ 9 &\sf Flourine & 1 \\ 10 &\sf Neon & 0 \\11 &\sf Sodium & 1 \\ 12 &\sf Magnesium & 2 \\ 13 &\sf Aluminium & 3 \\ 14 &\sf Silicon & 4 \\ 15 &\sf Phosphorus & 3 \\ 16 &\sf Sulphur & 2 \\ 17 &\sf Chlorine & 1 \\18 &\sf Argon & 0 \\ 19 &\sf Potassium & 1 \\ 20 &\sf Calcium & 2 \\ 21 &\sf Scandium & 3 \\ 22 &\sf Titanium & 4 \\ 23 &\sf Vanadium & 5,4 \\ 24 &\sf Chromium & 2 \\25 &\sf Manganese & 7,4,2 \\26 &\sf Iron & 2,3 \\ 27 &\sf Nickel & 3,2 \\ 28 &\sf Cobalt & 2 \\ 29 &\sf Copper & 2,1 \\ 30 &\sf Zinc & 2 \\ \end{array}$