Question

show the formation of sodium oxide by transfer of electrons​

Answer 1

The formation of sodium oxide by transfer electrons :

Atomic number of Sodium (Na) – 11.

Electronic configuration of Sodium – 1s2 2s2 2p6 3s1.

It has one valence electron, it will lose one electron to get octet configuration.

Atomic number of Oxygen (O) – 8.

Electronic configuration of Oxygen – 1s2 2s2 2p4.

It is two electrons short of octet configuration, thus it will gain two electrons.

During the bond formation between Sodium and Oxygen, two Sodium atoms loses one electron each to Oxygen atom.

2 Na -2e- → 2Na+ O + 2e- → O-2 2Na+ + O-2 → Na2O