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• Given :
Side of the cubes = 10 cm
(a) When three cubes are joined end to end, then
Length = 10 + 10 + 10 = 30 cm
Breadth = 10 cm
Height = 10 cm
We know that;
Surface area of cuboid= 2 ( lb + bh + hl )
⇒ 2 ( 30 × 10 + 10 × 10 + 10 × 30 ) cm²
⇒ 2 ( 300 + 100 + 300 ) cm²
⇒ 2 × 700
⇒ 1400 cm²
Hence, the surface area of resulting cuboid is 1400 cm².
( b ) Surface area of one cube = 6 a²
⇒ 6 × 10 × 10
⇒ 600 cm²
Surface area of three cubes = 3 * 600
⇒ 1800 cm²
Ratio of surface area of cuboid to the sum of surface area of three cubes :
Hence the ratio is 7 : 9.
• Given :
Side of the cubes = 10 cm
(a) When three cubes are joined end to end, then
Length = 10 + 10 + 10 = 30 cm
Breadth = 10 cm
Height = 10 cm
We know that;
Surface area of cuboid= 2 ( lb + bh + hl )
⇒ 2 ( 30 × 10 + 10 × 10 + 10 × 30 ) cm²
⇒ 2 ( 300 + 100 + 300 ) cm²
⇒ 2 × 700
⇒ 1400 cm²
Hence, the surface area of resulting cuboid is 1400 cm².
( b ) Surface area of one cube = 6 a²
⇒ 6 × 10 × 10
⇒ 600 cm²
Surface area of three cubes = 3 * 600
⇒ 1800 cm²
Ratio of surface area of cuboid to the sum of surface area of three cubes :
Hence the ratio is 7 : 9.
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