Show the function f of x is equal to x cube minus 3 x square + 6 x minus under increasing or not
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Answer:
x³ - 3x² + 6x - 100 is an increasing function
Step-by-step explanation:
Show the function f of x is equal to x cube minus 3 x square + 6 x minus 100 increasing or not
x³ - 3x² + 6x - 100
f(x) = x³ - 3x² + 6x - 100
f(x+1) = (x+1)³ -3(x+1)² + 6(x+1) - 100
f(x+1)= x³ + 1 + 3x² + 3x - 3(x² + 1 + 2x) + 6x + 6 - 100
f(x+1)= x³ - 3x² + 6x - 100 + (3x² -3x + 4)
f(x+1) - f(x) = 3x² - 3x + 4
= 3x² - 3x + 3/4 + 13/4
= 3(x² - x + 1/4) + 13/4
= 3(x- 1/2)² + 13/4
as (x- 1/2)² ≥ 0
so 3(x- 1/2)² + 13/4 ≥ 13/4 > 0
so we can say function is increasing
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