show the given pair is composite prime,? =161, 192?
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Step 1. Divide the larger number by the smaller one:
192 ÷ 161 = 1 + 31;
Step 2. Divide the smaller number by the above operation's remainder:
161 ÷ 31 = 5 + 6;
Step 3. Divide the remainder from the step 1 by the remainder from the step 2:
31 ÷ 6 = 5 + 1;
Step 4. Divide the remainder from the step 2 by the remainder from the step 3:
6 ÷ 1 = 6 + 0;
At this step, the remainder is zero, so we stop:
1 is the number we were looking for, the last remainder that is not zero.
This is the greatest common factor (divisor).
Step-by-step explanation:
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