Question

show the increasing order of energy of 1st Bohr orbit for H, He+,Li²+, Be³+ with explanation ​

Answer 1

Answer:

Correct order of radius of the first orbit of H,He+,Li2+,Be3+ is : · Correct order of radius of the `Ist` ordit of `H, He^ · The radius ratio of Bohr's first ...

Answer 2

As we know that, energy in the $n^{th}$ shell can be determined by:

$E= -13.6\frac{Z^2}{n^2} ev/atom$;

where n represents the shell or orbit of the atom which is given as 1 in the question and Z represents the atomic number of an atom.

From the formula, we can conclude that,

$E$ α $Z^{2}$, means energy is directly proportional to the square of the atomic number of element.

So, Value of Z for the given species in the question are-

$H = 1\\He^{+} = 2\\Li^{+2} = 3\\Be^{+3} = 4$

Hence, the correct increasing order of the energy is;

$H < He^{+} < Li^{+2} < Be^{+3}$