show the motion of a simple pendulum is simple Harmonic and hence derive an equation for its time period
Answers
Answer:
● Motion of pendulum as SHM -
[Refer to the figure]
Consider a simple pendulum with mass m and length l.
Let y and θ be its linear and angular displacements respectively.
θ = y/l
At extreme position,
Tangential acceleration is-
a = gsinθ
Torque about point of suspension is-
τ = -Fl
τ = -l(mgsinθ)
M.I. is related by-
τ = Iα
-l(mgsinθ) = Iα
When, θ is small, sinθ = θ,
α = -lmgθ/I
Comparing this with std eqn of SHM ω = √(mgl/I),
We can say that pendulum shows SHM.
● Period of oscillation-
T = 2π/ω
T = 2π/√(mgl/I)
Here, I = ml^2
T = 2π/√(mgl/ml^2)
T = 2π√(l/g)
Hope that was useful...
Explanation:
❤. SIMPLE PENDULUM: A metalic bob suspended by a light , torsionless, inextensible string is called simple pendulum.
❤. SECONDS PENDULUM : A pendulum with time period 2seconds is called seconds pendulum
❤. Kindly refer the above attachment