Question

show the polynomial
$x { }^{2} + 6x + 11$
has no zero.

Answer 1

Hello user !!

Your answer !!

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$x{ }^{2} + 6x + 11$

Let's try discriminent method here ..!!

$D = b{ }^{2} - 4 ac \\ D = 6 { }^{2}- 4 (1 ) (11 ) \\ D = 36 - 44 \\ D = - 8$

Discriminent is negative hence It has no zeroes !

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