Question

show the polynomial
x^2 + 6x + 11
has no zero

Answer 1

Hello user !!

Your answer !!

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${x}^{2} + 6x + 11 = 0 \\ D = {b}^{2} - 4ac \\ D = {6}^{2} - 4 ( 1 ( 11 ) = 0 \\ D = 36 - 44 \\ D = - 8$

By using descriminent method we get negative value ! hence it has no zeroes !

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Answer 2

All polynomial as zeros i think ur trying to say there are no real zeros
if there is real zeros then b^2-4ac>=0
so
6^2-4×1×11=-8 which is less than zero so it is not satisying the condition which means no real solution