Question

Show the roots of the equation x^2-6x+10 =0 on the argand diagram

Answer 1

Answer:

Step-by-step explanation:

The given equation is $x^{2} -6x+10=0\\\\x^{2}-6x+9+1=0\\x^{2}-2*3*x+3^{2} +1=0\\(x-3)^{2}+1=0\\(x-3)^{2}=-1\\ x-3=\sqrt{-1} \\x=3+\sqrt{-1}$

Answer 2

Step-by-step explanation:

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