Question

show the second - degree equation. x (x + 1) =0​

Answer 1

Step-by-step explanation:

x(X+1) =0

X+1 =0/X

X+1 =0

X = 0-1

X = -1

Answer 2

Hope it helps you ! of yes then mark me as a brainlist and follow me thank you^^

Answer:

solution of quadratic equation( ax2+bx+c=0) is given by -

x=−b±b2−4ac√2a . . . (1)

Here, a = 1, b = 1 and c = 1  (x2+x+1=0)  

Just put the value of a, b and c in eq(1),

x=−1±12−4∗1∗1√2∗1  

x=−1±−3√2  

This is shows its have only imaginary roots.

As  i=−1−−−√.  

x=−1±i3√2  

So two roots are,

x=−1+i3√2  and  x=−1−i3√2.  

Hope it helps you !

or

f(x)=x2+x+1  

Roots of the equation  f(x)=0  will be

x=−b±b2−4ac−−−−−−−√2a  

x=−1±12−4(1)(1)−−−−−−−−−−√2(1)  

x=−1±3–√i2  

x=−1+3–√i2  and

x=−1−3–√i2  

are also complex cube roots of 1 and also denoted respectively as  ω  and  ω2 .