Question

show the square of any positive integer is of the form for 4 m + 1 for same m​

Answer 1

Here Is Your Ans

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Let , a be any positive integer and b = 4

When a = 4q + 1

Squaring both sides, we have,

a2 = (4q + 1)2

a2 = 16q2 + 1 + 8q

= 4(4q2 + 2q) + 1

= 4m + 1 (where m = 4q2 + 2q)

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