Question

show two tangent AB and AC to a circle with centre O having point of contact at the point B and C respectively​

Answer 1

Answer:

Tangent is perpendicular to radius at point of contact.

So, ∠ABO=∠ACO=90

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In a quadrilateral, the sum of the angles is 360

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.

∠BAC+∠BOC+∠ABO+∠ACO=360

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∴∠BAC+∠BOC=180

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∠BOC=180

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−40

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∠BOC=140

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So, option C is the answer

Step-by-step explanation:

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