Show two tangents AB and AC to a circle with centre O having point of contact at the point B and C respectively.
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Answer:
Tangent is perpendicular to radius at point of contact.
So, ∠ABO=∠ACO=90
∘
In a quadrilateral, the sum of the angles is 360
∘
.
∠BAC+∠BOC+∠ABO+∠ACO=360
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∴∠BAC+∠BOC=180
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∠BOC=180
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−40
∘
∠BOC=140
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So, option C is the answer
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