Question

Show with the help of a diagram, how will you connect three resistances of 2 Ω , 4 Ω and 6 Ω to obtain a resultant resistance of 3Ω .

Answer 1

Hey There !

Here's The Answer

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Given :

• Resistances ( 2 Ω , 4 Ω and 6 Ω )
• Resultant resistance is 3 Ω

Solution :

• To obtain resultant resistance as 3 Ω using resistances of

2 Ω , 4 Ω and 6 Ω

Calculation :

Putting Resistor of 2 Ω , 4 Ω in series, we get resultant as

=> R = R₁ + R₂

=> R = 2 + 4

=> R = 6 Ω

• Now, putting 6 Ω resistor in parallel

=> 1/R = 1/R₁ + 1/R₂

=> 1/R = 1/6 + 1/6

=> 1/R = 2/6

=> 1/R = 1/3

=> R = 3 Ω

Hence, To obtain resultant resistance as 3 Ω using resistances of 2 Ω , 4 Ω and 6 Ω, we have to join series of 2 Ω and 4 Ω with parallel to 6 Ω.

It will be more clear by attachment.

Hope It Helps.