Question

show with the help of a diagram how will you connect three resistors each of resistance 6 ohm so that the combination has resistance of first 9 ohm second 4 ohm?.

Answer 1

(i) Two resistors in parallel

Two 6 Ω resistors are connected in parallel. Their equivalent resistance will be

The third 6 Ω resistor is in series with 3 Ω. Hence, the net resistance of the circuit is 6 Ω + 3 Ω = 9 Ω.

(ii) Two resistors in series

Here Rs=6+6=12 Ω let third resistance R3=6 Ω

Two 6 Ω resistors are in series. Their equivalent resistance will be the sum

∴ the total resistance is 4 Ω.

Answer 2

hope this will help u