show x-3 is a factor of f(x)= x^3+x^2-17x+15
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Answered by
3
Let x - 3 is a factor of x³ + x² - 17 x + 15
Then x - 3 = 0
x = 3
Substitute the value in x³ + x² - 17 x + 15
then
3³ + 3² - 17*3 + 15 = 0
27 + 9 - 51 + 15 = 0
51 - 51 =0
0 = 0
Hence it is a factor
Then x - 3 = 0
x = 3
Substitute the value in x³ + x² - 17 x + 15
then
3³ + 3² - 17*3 + 15 = 0
27 + 9 - 51 + 15 = 0
51 - 51 =0
0 = 0
Hence it is a factor
nikki170:
thanx
Answered by
1
Hello friend,
Here's your answer:
(x - a) if a factor of f(x), then f(a) = 0.
Here x - 3 is a factor of f(x).
Where f(x) = x³ + x² - 17x + 15.
So As x - 3 = 0
=> x = 3.
Therefore
f(3) = 3³ + 3² - 17×x + 15
=> 27 + 9 - 51 + 15
=> 51 - 51
=> 0
f(3) = 0.
Hence proved that x - 3 is a factor of x³ + x² - 17x + 15
Hope my answer helped you.
Harith
Maths Aryabhatta
Brainly Star
Here's your answer:
(x - a) if a factor of f(x), then f(a) = 0.
Here x - 3 is a factor of f(x).
Where f(x) = x³ + x² - 17x + 15.
So As x - 3 = 0
=> x = 3.
Therefore
f(3) = 3³ + 3² - 17×x + 15
=> 27 + 9 - 51 + 15
=> 51 - 51
=> 0
f(3) = 0.
Hence proved that x - 3 is a factor of x³ + x² - 17x + 15
Hope my answer helped you.
Harith
Maths Aryabhatta
Brainly Star
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