Question

show your solutions follow the steps and then answer ​

Answer 1

Answer:

1. c

2.a

3.c

4.c

5.a

Step-by-step explanation:

1.x² = 1

(a) 2x+5 = 11 is not a quadratic equation. It is a linear equation.

(c) x² = 1 => x²-1 = 0 is a quadratic equation.

(b) 1/x+6 = 3 => (1+6x)/x = 3

=> (1+6x) = 3x

=> 1 = 3x-6x

=> 1 = -3x

=> 3x+1 = 0 is not a quadratic equation. It is a linear equation.

(d) x³-x = 4 is not a quadratic equation. It is a cubic equation.

2.a

In the equation ax²+bx+c = 0 , a should not equal to zero.a ≠ 0

Reason : If a = 0 then the equation becomes

bx+c = 0 which is a linear equation.

3.3x²+4x-5 = 0

The equation 3x²+4x-5 = 0 is in the standard form

Since the standard quadratic equation is

ax²+bx+c = 0

4. c = 5

Given equation is 8x+3x² = -5

=> 3x²+8x+5 = 0

On comparing with the standard quadratic equation ax²+bx+c = 0

a = 3

b = 8

c = 5

5. b = 0

Given equation is x² = 4

=> x²-4= 0

=> x²+0x-4 = 0

On comparing with the standard quadratic equation ax²+bx+c = 0

a = 1

b = 0

c = -4