show your solutions follow the steps and then answer
Answers
Step-by-step explanation:
1)
Given equation is x²+2x = -1
=> x²+2x+1 = 0
The standard form = x²+2x+1 = 0
2)
Given equation is y²+3 = y+5
=> y²+3-y-5 = 0
=> y²-y+(3-5) = 0
=> y²-y-2 = 0
The standard form = y²-y-2 = 0
3)
Given equation is -(y+2)(y-1) = 3
=> -[y(y-1)+2(y-1)] = 3
=> -(y²-y+2y-2) = 3
=> -(y²+y-2) = 3
=> -(y²+y-2) -3 = 0
=> -(y²+y-2+3) = 0
=> -(y²+y+1) = 0
=> y²+y+1 = 0
The standard form is y²+y+1 = 0
4)
Given equation is x(x+9)+15 = -1
=> x²+9x+15 = -1
=> x²+9x-15+1 = 0
=> x²+9x-14 = 0
The standard form is x²+9x-14 = 0
5)
Given equation is x+(6/x) = -5
=> (x²+6)/x = -5
=> x²+6 = -5x
=> x²+6+5x = 0
=> x²+5x+6 = 0
The standard form is x²+5x+6 = 0
6)
Given equation is 5/(3n-8) = n/(n+2)
On applying cross multiplication then
=> n(3n-8) = 5(n+2)
=> 3n²-8n = 5n+10
=> 3n²-8n -5n -10 = 0
=> 3n²-13n-10 = 0
The standard form is 3n²-13n-10 = 0
Used formulae:-
The standard quadratic equation is ax²+bx+c = 0
Step-by-step explanation:
1. x^ + 2x + 1 = 0
2. y^ + y + 8 = 0
3. y^ - 2y = 0
4. x^ + 9x + 16 = 0
5. x^ + 4x + 6 = 0