Question

show3√3 is an irrational number​

Answer 1

Step-by-step explanation:

Lets assume 3√3 be an rational number

$3 \sqrt{3 } = \frac{a}{b}$

(where A and b are co-prime numbers and b is not equal to zero)

$\sqrt{3} = \frac{a}{3b}$

√3 is a rational number (because a/3b is a rational number)

but this contradicts the fact that √3 is irrational

Thus are assumption that 3√3 is irrational is wrong

therefore 3√3 is irrational

Hence,proved.