Shown below are three circles, P, Q and R. Their centres are C1 , C2 and C3 respectively.
The radius of circle P is 2 cm.
What is the DIAMETER of circle R?
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Step-by-step explanation:
ΔPC
1
A,ΔPC
2
B,ΔPC
3
C in one angle is 90
o
& angle P is common, then above triangle will be similar.
Hence for ΔPC
1
A & ΔPC
2
B
r
1
PA
=
r
2
PB
.........(i)
ΔPC
2
B & ΔPC
3
C
r
2
PB
=
r
3
PC
.........(ii)
we know that if tangents are drawn from an external point P to 3-circles
PA⋅PC=PB
2
or
PB
PA
=
PC
PB
r
2
r
1
=
r
3
r
2
r
2
=
r
1
r
3
.
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