Shown below is triangle ABC. Calculate the perimeter of the triangle.
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•P = (1,2)
•Q = (1,6)
•R = (-4,2)
Prove that PQR is a traingle
By applying the formula ,
• PQ = √[(1-1)²+(2-6)²]
= √[(16)]
= 4
PR = √[(1-(-4))²+(2-2)²]
= √[5²]
= 5
RQ = √[(-4-1)²+(2-6)²]
= √[25+16]
= √[41]
According to Pythagorean theorem ,
• consider LHS ,
• Hyp² = √[41]²
= 41
• Now RHS ,
• base ² + alt ² = 4² + 5²
= 16 + 25
= 41
Since LHS = RHS ,
it can be concluded that this is a right traingle
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