Shows a 15-cm-diameter loop in three different magnetic field
Answers
Answer:
εinduced= - (ΔΦb/Δt) εinduced= -0.50 T/sec ⋅ π ⋅ 0.052m2 εinduced= -3.93 × 10-3 V For part A: The flux is increasing, and the external magnetic field is going upward through the loop, so shouldn't the induced magnetic field go in opposite direction (downward) to oppose the external magnetic field? And so therefore shouldn't the induced current be clockwise around the loop according to the right hand rule? b) the flux is decreasing and the magnetic field is going into the loop (into the page). So since the flux through the loop is decreasing wouldn't this say that the the induced magnetic field goes in same direction of external magnetic field to try and prevent the decrease; and thus the
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