shows a brick of weight2Nand dimensions20cm×10×cm×5cmplaced in three different positions on the ground. Find the pressure exerted by the brick in each case.
Attachments:
Answers
Answered by
0
Pressure(N/m^-2) = force(N)/area(m^2)
Case 1) P=2/0.1×0.2=2/0.02=100
Case 2) P=2/0.05×0.1=2/0.005=400
Case 3) P=2/0.05×0.2=2/0.010=200
:-)
Answered by
2
Weight of brick = Thrust = F = 2 kgf
(a) Area of base = area of top L × B
= 20 Cm × 10
= 200 cm sq.
(b) area of base = area of top
= 5 cm × 10 cm
= 50 cm sq.
pressure exerted = P = F/A
= 2 kgf / 50 cm sq.
= 0.04 kgf cm (-sq).
(c) Weight of brick ,
F = 2 kgf
Area of base = L × B
= 20 cm × 5 cm
= 100 cm sq.
hopefully its helped u dear :)
Attachments:
Similar questions