Math, asked by PAKIZAALI, 6 months ago

shows thacos 0/1-sin0 +cos0/1-sin0 = 2sec0​

Answers

Answered by Anonymous
4

Step-by-step explanation:

LHS=sin0-cos0+1/sin0+cos0-1

on dividing by cos0 up and down,then

tan0+se0-1/tan0-sec0+1

= sec0+tan0-(sec20-tan20)/tan0-sec0+1

= sec0+tan0-{(sec0+tan0)(sec0-tan0)}/tan0-sec0+1

=sec0+tan0(1-sec0+tan0)/tan0-sec0+1

=sec0+tan0*(sec0-tan0)/(sec0-tan0)

=(sec20-tan20)/(sec0-tan0)

=1/sec0-tan0)

=RHS

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