Shows that sin(x-150°) + sin (x+30°) = 0
Answers
Answered by
1
sin( x +30) = sin (x + 180-150) = - sin (x- 150)
so sin(x-150) + sin(x+30 )=sin(x-150 ) - sin(x-150 )
=0
since sin( 180-x)= - sinx
so sin(x-150) + sin(x+30 )=sin(x-150 ) - sin(x-150 )
=0
since sin( 180-x)= - sinx
Answered by
1
Hey mate here is ur answer ******
__________________
sin(x-150°)+sin(x+30°)
=2 sin(x-150°+x+30°)/2 cos(x-150°-x-30°)/2
=2 sin (x-60°) cos90°
=0[Proved]
Hope it will help u@@@@####
__________________
sin(x-150°)+sin(x+30°)
=2 sin(x-150°+x+30°)/2 cos(x-150°-x-30°)/2
=2 sin (x-60°) cos90°
=0[Proved]
Hope it will help u@@@@####
soh2:
please mark my answer as brainliest
Similar questions