Showthat(a–b) ,(a +b )and(a+b) are in AP.
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turn b upside down to get p and capitalize a to get A
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2
Answer:
Assume that
(a−
b)
2
,(a
2
+
b 2
and
(a+
b)
2
are in AP.
So, difference between two consecutive terms will be same.
(a
2
+
b 2
(a− b)
2
= (a+ b)
2
− (a
2
+
b 2
(a
2
+
b 2
(a
2
+
b 2
2ab)=
a 2
b 2
2ab−
a 2
b 2
2ab= 2ab
Which is true.
Hence given terms are in AP.
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