Question

showthat.

(x+2) will be a factors of
f (x) = will x^4-x^2-12​

Answer 1

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Given :

p (x) = x^4 - x^2 - 12

(x+2) is a factor

so let

x + 2 = 0

x = -2

So,

now substitute this value in place of X

$p(x) = {x}^{4} - {x}^{2} - 12 \\ p( - 2) =( - 2 {)}^{4} - ( - 2 {)}^{2} - 12 \\ = 16 - 4 - 12 \\ = + 16 - 16 \\ = \: \: \: 0$

Therefore,

(x+2) is the factor of p (x).

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